How to keep css id to the 'li' in css

Tags: html,css,css3

Problem :

The below vertical navigation work perfect but. i would like to change the html code from

<ul id="menu">
<li ><a href=""><span>Hello</span></a></li>
<li ><a href=""><span>Hello</span></a></li>
<li ><a href=""><span>Hello</span></a></li>
<li ><a href=""><span>Hello</span></a></li>


<li id="menu" ><a href=""><span>Hello</span></a></li>
<li id="menu"><a href=""><span>Hello</span></a></li>
<li id="menu"><a href=""><span>Hello</span></a></li>
<li id="menu"><a href=""><span>Hello</span></a></li>

It doesn't works. I would like to keep the id for li not for ul . Is i pass id to li ,it doesn't show the image.

#menu ul
margin: 0px;
padding: 0px;
list-style-type: none;

#menu a
display: block;
color: #333;
font-family: "Helvetica Neue", Helvetica, Arial, sans-serif;
  background: #ffffff;

border-bottom: 1px solid #ccc;
width: 100%;
height: 2.72em;
line-height: 2.75em;
text-indent: 2em;
text-decoration: none;

#menu a:hover

background:-moz-linear-gradient(top,  #ffffff 0%, #f6f6f6 47%, #ededed 100%); 
background:-webkit-gradient(linear, left top, left bottom, color-stop(0%,#ffffff),  color-stop(47%,#f6f6f6), color-stop(100%,#ededed)); 
background:-webkit-linear-gradient(top,  #ffffff 0%,#f6f6f6 47%,#ededed 100%); 
background:-o-linear-gradient(top,  #ffffff 0%,#f6f6f6 47%,#ededed 100%); 
background:-ms-linear-gradient(top,  #ffffff 0%,#f6f6f6 47%,#ededed 100%);
background:linear-gradient(to bottom,  #ffffff 0%,#f6f6f6 47%,#ededed 100%); 
filter:progid:DXImageTransform.Microsoft.gradient( startColorstr='#ffffff',  endColorstr='#ededed',GradientType=0 ); 
#menu li a{ background:url('') no-repeat ;
 background-position:0% 50%;

#menu li a:hover{ background:url('') no-repeat   ;
background-position:0% 50%;

Solution :

You cant have more than 1 item with the same id, you will want to give the li a class of "menu"... then in your css change "#menu li a" to ".menu a"

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